Insert two procedure

Question

0.00/5 (No votes)

See more:

Hi,
I have a problem with my page. I have 2 procedure. First one is to select data from sql server and the second is to update the data if the row is change.

When I am running the procedure on C# they work, but when I run the both procedure it does not update the data. It does not recognize that I changed the data. My code:

C#

using System.Web.UI; 
using System.Web.UI.WebControls; 
using System.Data.SqlClient; 
using System.Data.SqlTypes; 
public partial class controll_update : System.Web.UI.Page 
{ 
SqlConnection con; 
SqlCommand cmd = new SqlCommand(); 
SqlDataReader rd = null; 
protected void Page_Load(object sender, EventArgs e) 
{ 
TextBoxid1.Text = Page.Request.QueryString["id"]; 
con = new SqlConnection("Server=localhost;Initial Catalog=shahar;Integrated Security=True;"); 
cmd = new SqlCommand("select_for_update", con); 
cmd.CommandType = CommandType.StoredProcedure; 
cmd.Parameters.Add("@id", SqlDbType.NChar, 20).Value = Page.Request.QueryString["id"]; 
con.Open(); 
rd = cmd.ExecuteReader(); 
if (rd.Read()) 
TextBoxfname1.Text = rd[1].ToString(); 
TextBoxid2.Text = rd[3].ToString(); 
TextBoxlname.Text = rd[2].ToString(); 
con.Close(); 

} 

protected void Button1_Click(object sender, EventArgs e) 
{ 
TextBoxid1.Text = Page.Request.QueryString["id"]; 
con = new SqlConnection("Server=localhost;Initial Catalog=shahar;Integrated Security=True;"); 
cmd = new SqlCommand("update_pro", con); 
cmd.CommandType = CommandType.StoredProcedure; 
cmd.Parameters.Add("@id", SqlDbType.NChar).Value = Page.Request.QueryString["id"]; 
cmd.Parameters.Add("@fname", SqlDbType.NChar).Value = TextBoxfname1.Text; 
cmd.Parameters.Add("@lname", SqlDbType.NChar).Value = TextBoxlname.Text; 
cmd.Parameters.Add("@id_num", SqlDbType.NChar).Value = TextBoxid2.Text; 
con.Open(); 
cmd.ExecuteNonQuery(); 
con.Close(); 
} 

protected void TextBoxfname1_TextChanged(object sender, EventArgs e) 
{ 

} 
protected void TextBoxlname_TextChanged(object sender, EventArgs e) 
{ 

} 
}

I dont have any error, it just goes back to original data.

Thank you

Posted 24-Sep-10 7:23am

anat1983

Updated 24-Sep-10 8:50am

Henry Minute

v3

Add a Solution

Comments

Henry Minute 24-Sep-10 14:50pm

Try to use more accurate tags when asking questions. It will improve your chances of getting an answer.

2 solutions

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

Not Active · Answer 1 · 2010-09-24T09:09:00

It is behaving exactly as you are telling it to. On the initial visit to the page the PgaeLoad event populates the textboxes from the database. After entering new text and clicking the button a postback is generated which causes the PageLoad event to fire once again, returning the textboxes to the original values from the database.

use IsPostBack

protected void Page_Load(object sender, EventArgs e)
{
  if(!IsPostBack)
  {
    // existing code
  }

}

anat1983 · Answer 2 · 2010-09-24T09:37:00

Solution 2

wow, it was so simple... thank you very much, it helped!!!

Posted 24-Sep-10 9:37am

anat1983

Comments

AspDotNetDev 24-Sep-10 15:49pm

FYI, you can add comments directly to answers rather than creating fake answers. Also, I'm sure Mark would appreciate it if you voted on his answer and accepted his solution (there is a button that allows you to do this).