How to split double number.

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My double number:

double inputValue = 48.4866666;

I want: inputValue = 48.48

inputValue = Math.Round(inputValue, 2);

What I have tried:

inputValue = Math.Round(inputValue, 2); but its give 48.49 and I need 48.48

Posted 4-Apr-17 21:29pm

Parmendra choudhary

Updated 4-Apr-17 21:46pm

v2

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Karthik_Mahalingam · Accepted Answer · 2017-04-04T21:34:00

Solution 1

check this similar thread with Solved Answers
c# - Get Last 2 Decimal Places with No Rounding [^]

Posted 4-Apr-17 21:34pm

Karthik_Mahalingam

OriginalGriff · Accepted Answer · 2017-04-04T21:36:00

Solution 2

Use Math.Truncate Method (Double) (System)[^]

C#

inputValue = Math.Truncate(inputNumber * 100.0) / 100.0;

Posted 4-Apr-17 21:36pm

OriginalGriff

Jochen Arndt · Accepted Answer · 2017-04-04T21:46:00

Round(Double, Int32) is rounding to nearest. If you need a different rounding mode use Math.Round Method (Double, Int32, MidpointRounding) (System)[^].
In your case:

C#

inputValue = Math.Round(inputValue, 2, MidpointRounding.AwayFromZero);

If you know that the input value is always valid and positive, you may also add half of the rounding position value:

C#

inputValue = Math.Round(inputValue + 0.005, 2);
For negative numbers you have to subtract.