Convert algorithm to C++

Question

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A program is to be written to input a a message in string and then encrypt the message.

output "Enter message"
Input MyMessage
EncryptString= ""

For i- 1 to CHARACTERCOUNT (mymessage)
NextNum - ASC(ONECHAR(MYMessage,i) + 3)
EncryptString - EncryptString & CHR(NextNum)
Endfor
Output encryptstring

ONECHAR("Barcelona", 3) returns 'r'
CHARACTERCOUNT ("South Africa") returns 12

What I have tried:

Please help me write this algorithm in C++

Mystring=Input ('key in string')

Stringtotal=0

for i in range (0,len(Mystring)):

NextNum = ord( Mystring[i])

StringTotal= StringTotal + NextNum

Print(MyString, stringTotal)

Have tried this in python help me convert it to C++

Posted 21-Jun-18 20:26pm

Member 13795308

Updated 22-Aug-20 4:55am

Patrice T

v4

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Jochen Arndt 22-Jun-18 3:08am

You do know Basic and C/C++?
If so, it is no problem to do it yourself.

If not, what is your task?
Convert that specific Basic code, but you don't know Basic?

Or do you have some kind of C++ homework, found that Basic code, and thought that it is doing what the assignment wants you to do?

Anyway, it is a ROT3 letter substitution cipher without handling roll-over. That means the code of each character is incremented by 3.

Member 13795308 22-Jun-18 3:20am

Have recently started c++ , gone through basic. Assignment was to convert it into python code which I have done but I want to experiment it in c++. I am quite new to it, so I could only do input and output but got stuck in the loop no idea how to write it

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Jochen Arndt · Accepted Answer · 2018-06-21T21:44:00

Quote:
Have recently started c++ , gone through basic. Assignment was to convert it into python code which I have done but I want to experiment it in c++. I am quite new to it, so I could only do input and output but got stuck in the loop no idea how to write it

Even your Python code is missing the +3 part.

But in C/C++ it is much simpler. If you have C string (char array) or a std::string you can access the array by index / [] operator:

C++

input[i] += 3;

Note that the above code snippet assumes that output has been initialised with a copy of the input string.

Alternatively use a Range-based for loop (since C++11) - cppreference.com[^] :

C++

// input is of type std::string
std::string output;
for (auto c : input)
    output += c + 3;

Richard MacCutchan · Accepted Answer · 2018-06-21T21:12:00

Solution 1

See C-C++ Language and Standard Libraries[^]

Posted 21-Jun-18 21:12pm

Richard MacCutchan