Why 2nd program should give unknown value for integer a?

Question

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C++

Main ()
{
 Char ch = 'A';                 
 ch = ch+1;
 printf ("%c", ch);
 Int a = ch;
 Printf ("%d", a);
}

OUTPUT:B66

C++

Main ()
{
 Char ch = 'A';
 ch = ch+1;
 Int a = printf ("%c", ch);
 Printf ("%d", a);           
}

OUTPUT:B1

why 2nd program should give an unknown value for integer a?

What I have tried:

The return type of printf function is an integer. Why cannot i store its value in int a?

Posted 23-Jul-18 3:58am

Member 13922884

Updated 23-Jul-18 4:10am

Kornfeld Eliyahu Peter

v2

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Kornfeld Eliyahu Peter · Accepted Answer · 2018-07-23T04:11:00

First of all - C/C++ is case sensitive, which means that your code goes nowhere as it is...

I assume you understand why the first snippet prints 'B66' so I explain the second one only...

printf - on success - returns the number of the characters printed, in your case 1, so a will be 1 and that will give you 'B1'