Converting string to integer in java

Question

1.00/5 (1 vote)

See more:

sample.java:7: error: cannot find symbol
i=Integer.parseInt(s);
^
symbol: method parseInt(String)
location: class Integer

error has occure while converting string to integer

java version "1.8.0_191"
javac 1.8.0_161

What I have tried:

class sample
{
	public static void main(String args[])
	{
		String s=new String("100");
		int i;
		i=Integer.parseInt(s);
		System.out.print(i);
	}	
}

Posted 20-Nov-18 5:53am

49R

Updated 20-Nov-18 6:26am

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Comments

Richard MacCutchan 20-Nov-18 12:19pm

I just tried that code and it works fine.

2 solutions

Solution 2

import java.lang.Integer;
class sample
{
	public static void main(String args[])
	{
		String s=new String("100");
		int i;
		i=Integer.parseInt(s);
		System.out.print(i);
	}	
}

Posted 20-Nov-18 6:27am

49R

Comments

Afzaal Ahmad Zeeshan 21-Nov-18 3:57am

That import is not required, it works without that too as well.

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Afzaal Ahmad Zeeshan · Accepted Answer · 2018-11-20T06:16:00

First off, the code works just fine and the output is 100 in my case, just tried in VS Code. So, show the code that is causing the problem.

Now, for the question, these two errors are different,

sample.java:7: error: cannot find symbol

and,

error has occure while converting string to integer

They both have a different meaning, thus sharing that they occur at 2 different instances. The first one, would mostly mean that you might be missing an import. Whereas, the second one meaning that you has passed in an in correct value of string, that cannot be mapped to a valid integer. A few things you can do,

Java

int value;
try {
   value = Integer.parseInt(s);
} catch (Exception e) {
   // Problem, 
}

This will ensure that incase there is a runtime exception during conversion, your app will not crash, instead will be given an opportunity to render a friendly message on the screen. If you try to check the documentation for the parseInt() function, you will see that it throws NumberFormatException, that is what you need to look for.

Integer (Java Platform SE 7 )[^]