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i am adding data from two text boxes into a listbox,i want to add the data in horizontal manner.suppose i add data from two text boxes i want them to be displayed in horizontal manner,and for the next entry they should be displayed below the previous entry.and also can a header be provided for the data to display what that data meant to be.(i know it can be done using list view, but i want to know whether it can be done using listbox)

name code <---header
sam 060
rob 061
Posted

1 solution

Do like this :

C#
//Create two classes

Class Person
{
private String name;
public String Name
{
get{return name;}
set{name=value;}
}

private int code;
public int Code
{
get{return code;}
set{code=value;}
}

//ctor
public Person(String name,int code)
{
Name=name;
Code=code;
}
}

Class PersonCollection:ObservableCollection<person>
{

}

//Go into the code-behind of your application
// Add this in your constructor

public Window1
{
InitializeComponent();
PersonCollection perColl=new PersonCollection();
listBox.ItemsSource=perColl;
}

//In the Add button event handler(that adds the value in ListBox), do this

perColl.Add(new Person(txtName.Text,int.Parse(txtCode.Text));</person>


Move over to your XAML :

XML
<listbox name="listBox">
<listbox.itemtemplate>
<datatemplate>
<stackpanel orientation="Horizontal">
<textblock text="{Binding" path="Name}/">
<textblock text="{Binding" path="Code}/">
</textblock></textblock></stackpanel></datatemplate>
</listbox.itemtemplate>
</listbox>


The Stackpanel above in your DataTemplate will keep the name and code in a horizontal way.

Hope it helped!
 
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v2
Comments
Sergey Alexandrovich Kryukov 23-Mar-11 17:39pm    
I'm confused. Will it make ListBox multi-column? How?
--SA
Tarun.K.S 24-Mar-11 4:06am    
Listbox can't be made multicolumn, for that ListView is a better choice. OP wanted the former way. :)
So with the DataTemplate, the data in each row will be displayed like this : Name Code.
Sergey Alexandrovich Kryukov 24-Mar-11 4:30am    
Thank you. I was confused because both are mentioned. I vote 5.
--SA
Tarun.K.S 24-Mar-11 4:34am    
Thanks a lot SA! :)
girish sp 24-Mar-11 3:17am    
@SAKryukov-u can do it..but datasource should be involved..but i forgot to mention no datasource is involved in my appln..can it be done.

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