XamDataTree when click right mouse , how to know mouse is on which Layout

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I used a XamDataTree control in my App and I want show different Menu when mouse right click on XamDataTree Nodes. problem is when click , how can I know mouse is on which Layout?

on my application , there is two Layout as blow:

NodeLayout mylayout = new NodeLayout();
mylayout.Key = "FristLayout";
mylayout.TargetTypeName = "Category";
mylayout.DisplayMemberPath = "CategoryName";

NodeLayout mylayout2 = new NodeLayout();
mylayout2.Key = "SecondLayout";
mylayout2.TargetTypeName = "Product";
mylayout2.DisplayMemberPath = "FileName";

I want to show one menu for FristLayout and different menu for SecondLayout.

is there any idea or help?

thanks in advance.

Posted 4-Jul-11 23:52pm

Alimjan Yasin

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Alimjan Yasin · Accepted Answer · 2011-07-05T00:42:00

I solved it , the idea is below:

1.Create Menu when Click event of XamDataTree.
2.Detect the selected Elements in the Opening Event of Menu,like below

var node = e.GetClickedElements<XamDataTreeNodeControl>().FirstOrDefault();
           if (node != null && node.Node.NodeLayout.Key == "FristLayout")
{
  //add menu items here
}
     
Done!