How to find current Inserted record in sql server

Question

1.00/5 (1 vote)

See more:

Hi,

I have tblCustomer table that contains 1000 records.
If i will distinct the records through custid field then it is showing me 650 records.

I have to retrieve 650 records from tblCustomer.
Here i have to find out latest record if the record has the duplicate as per the custid. Here is no any date fields.

plz give me the solution.

Bye

Posted 8-Nov-11 18:58pm

purnananda behera

Updated 8-Nov-11 19:24pm

v2

Add a Solution

Comments

[no name] 9-Nov-11 1:11am

Asking for a solution without even attempting anything, or showing that you have, is just plain rude.

1 solution

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

Not Active · Answer 1 · 2011-11-08T19:10:00

Solution 1

You can find the last record by querying for the max primary key value. What have you tried?

Posted 8-Nov-11 19:10pm

Not Active

Comments

purnananda behera 9-Nov-11 1:12am

I don't have any primary key also.

[no name] 9-Nov-11 3:28am

Then your database is very poorly constructed. Add a primary key.