How to get Top 1 record in left join

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My query is as below , i am getting two records with same ordernumber , i need only last top 1 order with left join.

SQL

select DATEDIFF(HOUR,gso.Date1,goh.Date2),gso.Date1,goh.Date2,gso.OrderNumber from tableA gso left join tableB goh on gso.OrderId = goh.OrderId and goh.StatusId =278 and goh.ActionId =0
where gso.OrderStatusId not in(185,488,486,870)
and DATEDIFF(HOUR,gso.Date1,goh.Date2) <-1
gso.orderDate > '01/01/2011 00:00:00 AM'

suppose for orderid =213537, there is two entries in tableB as bellow
OrderId UserId StatusId ActionId ChangedDate
213537 24249 278 0 2/26/2011 5:19:23 AM
213537 24249 278 0 2/28/2011 1:07:19 PM

i need to display last entry with above join query

Posted 27-Nov-11 20:44pm

sagar15modi

Updated 27-Nov-11 21:27pm

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[no name] 28-Nov-11 2:58am

clarify question pls.

2 solutions

Solution 1

try this,

SQL

select DISTINCT DATEDIFF(HOUR,gso.Date1,goh.Date2),gso.Date1,goh.Date2,gso.OrderNumber from tableA gso left join tableB goh on gso.OrderId = goh.OrderId and goh.StatusId =278 and goh.ActionId =0
where gso.OrderStatusId not in(185,488,486,870)
and DATEDIFF(HOUR,gso.Date1,goh.Date2) <-1
gso.orderDate > '01/01/2011 00:00:00 AM'

i assumed that your code wass free from errors, i just added the DISTINCT keyword,

hope it helps,

mark as answer if it helps you..

thanks

Posted 27-Nov-11 21:00pm

D K N T H

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sagar15modi · Accepted Answer · 2011-11-27T21:47:00

SQL

select DISTINCT DATEDIFF(HOUR,gso.Date1,goh.Date2),gso.Date1,goh.Date2,gso.OrderNumber from tableA gso left join tableB goh on gso.OrderId = goh.OrderId and goh.StatusId =278 and goh.ActionId =0
and goh.Date2 = (select max(goh1.Date2) from tableB as goh1 where OrderId =goh.Orderid and goh1.StatusId =278)
where gso.OrderStatusId not in(185,488,486,870)
and DATEDIFF(HOUR,gso.Date1,goh.Date2) <-1
gso.orderDate > '01/01/2011 00:00:00 AM'