Find all repeating numeric strings within a textbox

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Using Visual Studio 2008 I have a code that generates random characters depending on the current date. When time is not changing fast enough, or the program begins to malfunction, I have repeating numbers. each numeric string is placed into a textbox and each time the numeric string is produced, it is placed into a new line. I need a code snippet that will find these repeating string which contain a number like so:
162763-115235-205.2218

I need a piece of code that will show the repeated strings in another textbox for each repeated instance.

Thank You.

[edit]
Just a description of what my application does.
User presses button.
numeric text generates into the text box.
each line in the text box is a separate value.

now what I need to do is find each "value" that repeats and say so in another textbox.

thanks.
[/edit]

Posted 23-Feb-12 12:02pm

vlad781

Updated 24-Feb-12 14:38pm

v5

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Manfred Rudolf Bihy · Accepted Answer · 2012-02-23T12:11:00

Just put all the Strings you produced into a List and then let loose the power of Enumerable.Distinct(Of TSource)-Methode (IEnumerable(Of TSource))[^].

[Edit]
While taking set differences may also have been an option I tried a different approach from above utilizing LinQ queries:

C#

public static void CountAllDoubles()
{
    // Create a list of String.
    List<String> listOfStrings = new List<String>{ "AAA", "BBB", "CCC", "AAA", "CCC", "AAA", "DDD" };

    var query = listOfStrings.GroupBy(
        element => element,
        (element, elements) => new
        {
            Key = element,
            Count = elements.Count(),
        });

    Console.WriteLine("Counting all occurrences including single ones:");
    foreach (var result in query)
    {
        Console.WriteLine("\tString: {0} Number of occurrences: {1}", result.Key, result.Count);
    }


    Console.WriteLine("\nCounting only multiple occurrences:");
    foreach (var result in query.Where(a => { return a.Count > 1;  }))
    {
        Console.WriteLine("\tString: {0} Number of occurrences: {1}", result.Key, result.Count);
    }
}

[/Edit]

Regards,

Manfred

As a side note, I just had an opportunity to use this today.