Check all elements of an array

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Hello,

I would like to create some sort of function that checks all the values of an array and, if they are all the same, sets a bool to false, and if one of the values is different then the rest, sets the bool to true.

Example:
Say the array1 contains {0, 0, 0} and array2 contains {0, 1, 0}

int Array[3];
bool TheBool(false);

for(int i = 0; i < SizeOfArray; i++)
{
  if(all elements of the array are the same)
  {
    TheBool = false;
  }
  else
  {
    TheBool = true;
  } 
}

With array1, TheBool should be false, and with array2, it should be true.

Thanks in advance to anyone who can help me out with this :)

Posted 26-Mar-12 4:51am

LucasShadow

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Pablo Aliskevicius 26-Mar-12 11:13am

This looks like a homework question. If so, please say so.

LucasShadow 26-Mar-12 15:20pm

No its not a homework question. Its something I am just trying to figure out myself as I continue to self-teach myself c++

enhzflep 26-Mar-12 11:26am

So why not do it the same way you'd do it on a piece of paper with a list of numbers?

That is to say,

For all elements except first one:
if (currentElement != previousElement) allSame = false

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Fredrik Bornander · Answer 1 · 2012-03-26T05:25:00

A naive implementation could be something like this;

C++

#include <iostream>

using namespace std;

bool checkArray(int a[], size_t length)
{
	if (length < 2)
		return true;
	else
	{
		int value = a[0];
		for(int i = 1; i < length; ++i)
		{
			if (a[i] != value)
				return false;
		}

		return true;
	}
}

int main()
{
	int myArray[3];
	myArray[0] = 1;
	myArray[1] = 2;
	myArray[2] = 1;

	cout << (checkArray(myArray, 3) ? "All are same" : "There are different numbers in there!") << endl;
	return 0;
}

Hope this helps,
Fredrik