sql query to find distinct result for every user

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hello freinds
i have a probulm in sqlserver query.
i have a table having records like this.

Bill no     userid      amt          billenterdate
1            1         100              2012-05-24 05:29:35.223
2             2          200               2012-03-24 05:29:35.223
3             2          200            2012-01-24 05:29:35.223
4              1           2000             2012-05-4 05:29:35.223

--------------------------------------------------------------------

now i want to select a single record for each userid where billenter date is maximum from that users all records.

result should be:-

1       1         100    2012-05-24 05:29:35.223
2       2          200   2012-03-24 05:29:35.223

please help me how to achieve this result

Posted 24-May-12 0:34am

pawanvats

Updated 24-May-12 0:44am

Maciej Los

v3

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3 solutions

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Jiten.s.ims · Answer 1 · 2012-05-24T01:57:00

Solution 2

SQL

Select BillNo,userid, amt, billenterdate
From
(
    SELECT
        BillNo,userid, amt, billenterdate, Rank() over (Partition BY userid order by Cast(Convert(varchar,billenterdate,106) as datetime) Desc) as [Rank]
    FROM
    TblBillDetails
) A
where [Rank]=1

Posted 24-May-12 1:57am

Jiten.s.ims

Comments

Maciej Los 24-May-12 8:42am

Great answer, my 5!

Jim Jos · Answer 2 · 2012-05-24T01:58:00

Solution 3

Another solution using subquery and inner join

SQL

select * from Table_1 a 
inner join (select max(billenterdate) as billenterdate,userid from Table_1 group by userid) as userinfoTable 
on a.billenterdate = userinfoTable.billenterdate and a.userid = userinfoTable.userid order by billno

Posted 24-May-12 1:58am

Jim Jos

Wendelius · Answer 3 · 2012-05-24T11:00:00

Solution 4

Or a correlated EXISTS structure

SQL

SELECT *
FROM   YourTable t1
WHERE  NOT EXISTS (SELECT 1
                   FROM   YourTable t2
                   WHERE  t2.UserId        = t1.UserId
                   AND    t2.BillEnterDate > t1.BillEnterDate)

Posted 24-May-12 11:00am

Wendelius