Creating a new row in datagrid with Bgw progress update

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I have a file im pulling data from which loads into a data grid view. When its loading it locks the application up and i need to be able to use the application while its loading. Below is how im loading the rows:

VB

DgwApping.rows.add(name, address, size, date, status)

i know that a background worker has a progress method but it only lets me add one item and the progress status. how can i load an entire row from a background worker? Thanks for the help.

Posted 25-Jul-12 13:57pm

Zachary.shupp

Updated 25-Jul-12 13:59pm

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Christian Graus · Answer 1 · 2012-07-25T13:59:00

Solution 1

If you're using the file system, then while the file is open in one thread, no other thread can open it. This is why it's better to use a database. Alternatively, read the whole file in to memory and then process it there, instead of keeping the file open. Of course, you don't want each thread to read in a monolithic file, so if it's rarely changing, you're better off making it a static property on the site, and perhaps writing code that checks the last changed date against one you store, to see if it needs reloading.

Posted 25-Jul-12 13:59pm

Christian Graus

Comments

Zachary.shupp 25-Jul-12 20:22pm

This file change frequently and we check it on different machines. I just need to find someway to pass multipe items throgu the progresschanged event. I have tried creating a list but it dosent like that.

Christian Graus 25-Jul-12 20:46pm

You could pass a string as XML if all else fails ? It does sound like your file should be data in a DB. You should post the actual code that reads the file if you want more specific advice.

Zachary.shupp 25-Jul-12 21:10pm

Could u give me an example

Christian Graus 25-Jul-12 21:11pm

An example of what XML is ?