C++ regex find the string between two brackets

The regex I prepared for php (I don't know if there is a different build in c ++)  on https://regex101.com/: 

    (?<=deneme\()([^]]+)(?=\))

Target string:

    deneme("deneme", 1,2,deneme2(), 3, "3123", sda())

Expected output:
   
    "deneme", 1,2,deneme2(), 3, "3123", sda()

I can't give an example code because I don't know anything about regex in c ++. How can I get the expected output on c ++ based on the examples I gave above?


this code works in c # and gives the output I want. I don't know how to convert it to c ++.

```cs
using System;
using System.Text.RegularExpressions;

public class Example
{
    public static void Main()
    {
        string pattern = @"(?<=deneme\()([^]]+)(?=\))";
        string input = @"deneme(""deneme"", 1,2,deneme2(), 3, ""3123"", sda())";
        RegexOptions options = RegexOptions.Multiline;
        
        foreach (Match m in Regex.Matches(input, pattern, options))
        {
            Console.WriteLine("'{0}' found at index {1}.", m.Value, m.Index);
        }
    }
}
```

I can also write a related code with php. but I am also confused in c ++.
```php
$re = '/(?<=deneme\()([^]]+)(?=\))/m';
$str = 'deneme("deneme", 1,2,deneme2(), 3, "3123", sda())';

preg_match_all($re, $str, $matches, PREG_SET_ORDER, 0);

// Print the entire match result
var_dump($matches);
```

I haven't had experience as I don't have enough knowledge of std :: regex to dump what I want into c ++ code.