Why I am getting segmentation fault error here?

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Here there is segmentation fault here, why?

What I have tried:

C++

#include<stdio.h>
int findmid(int [],int);
int main()
{
    int n,c,i;
    int a[n];
    printf("Enter the valu of n :");
    scanf("%d",&n);
    int x;
    for(i=0;i<n;i++)
    scanf("%d",&a[i]);
    x=sizeof(a)/sizeof(int);
    c=findmid(a,x);
    printf("%d",c);
    return 0;
}

int findmid(int a[],int x)
{
    return a[x/2];
}

Posted 10-May-21 1:35am

_-_-_-me

Updated 10-May-21 3:42am

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OriginalGriff · Answer 1 · 2021-05-10T01:50:00

Solution 1

See my answer to your previous question: Size of an array in the programme[^]

Posted 10-May-21 1:50am

OriginalGriff

CPallini · Answer 2 · 2021-05-10T01:55:00

Solution 2

See also my answer to your previous question: Size of an array in the programme[^]
:D

Posted 10-May-21 1:55am

CPallini

Patrice T · Answer 3 · 2021-05-10T03:42:00

Quote:
Why I am getting segmentation fault error here?

Because your code is wrong

C++

#include<stdio.h>
int findmid(int [],int);
int main()
{
    int n,c,i;
    int a[n]; // you can't allocate an array dynamically sized at runtime
    printf("Enter the valu of n :");
    scanf("%d",&n); // before knowing the size
    int x;
    for(i=0;i<n;i++)
    scanf("%d",&a[i]);
    x=sizeof(a)/sizeof(int);
    c=findmid(a,x);
    printf("%d",c);
    return 0;
}

int findmid(int a[],int x)
{
    return a[x/2];
}