How does the following list comprehesion works in simple statments?

Question

1.00/5 (1 vote)

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return [
    x for x in nums
    if x % 2 != Counter([n % 2 for n in nums]).most_common()[0][0]
  ]

What I have tried:

<pre>

for x in nums:
for n in nums:

if x % 2 != Counter([n % 2 for n in nums]).most_common()[0][0]

return x

Posted 27-Oct-21 18:52pm

shah faisal khan

Updated 28-Oct-21 5:07am

v2

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Comments

Richard MacCutchan 28-Oct-21 4:26am

Separate each part out of the statement and run it in the Python ide and you will see.

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Richard MacCutchan · Accepted Answer · 2021-10-28T05:07:00

As mentioned in my comment run the following in order in a Python shell or IDE:

Python

Counter([n % 2 for n in nums]) # returns the counts of odd and even numbers
Counter([n % 2 for n in nums]).most_common() # as above but ordered by count descending
Counter([n % 2 for n in nums]).most_common()[0] # the set with the most entries (odd numbers or evens)
Counter([n % 2 for n in nums]).most_common()[0][0] # 1 or 0 depending on which are most common.

as for the rest, you need to find out what it is supposed to be doing.