[C] shifting the pointer

#include <stdio.h>

int main()
{
 
    char* arr[3] = { "geek", "Geeks", "Geeksfor" };

    for (int i = 0; i < 3; i++) {
        printf("*(arr+%d) : %p\n", i, *(arr+i));
    }
    printf("\n");
    for (int i = 0; i < 3; i++) {
        printf("  arr+%d  : %p\n", i, arr+i);
    }
    printf("\n");
    for (int i = 0; i < 3; i++) {
        printf(" &arr+%d  : %p\n", i, &arr+i);
    }
    printf("\n");
 
    return 0;
}

1. printf("Indeks : %d, Address of (arr) : %p\n",i , *(arr+i));
   
2. printf("Indeks : %d, Address of (&arr) : %p\n",i , arr+i);
   
3. printf("Indeks : %d, Address of (&arr) : %p\n",i , &arr+i);
   

1. You take the content of arr + i, which is a pointer which points to a string of characters and will be allocated by the compiler. Its actual value has nothing to do with pointer arithmetic, it is purely a random address as allocated by the compiler.
   
   
2. You take the actual pointer at arr + i and print its address. And since it is one of three pointers, they will each be 8 bytes distant from their predecessor.
   
   
3. You are printing the address of the array itself, plus 0, 1 and 2. And since the array is 3 pointers in size, this address will increase by the size of the array itself.