Opening Visual Studio 2008 with a button in WinForms Visual Studio 2012

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private void btnReport_Click(object sender, EventArgs e)
        {
            Process openVisualStudio2008 = new Process();
            openVisualStudio2008.StartInfo.FileName = @"C:\Program Files(x86)\Microsoft Visual     Studio 9.0\Common7\IDE\devenv.exe";
            openVisualStudio2008.Start();
        }

How can I specify the filename correctly, because if I change the Filename to

private void btnReport_Click(object sender, EventArgs e)
        {
            Process openVisualStudio2008 = new Process();
            openVisualStudio2008.StartInfo.FileName = "devenv.exe";
            openVisualStudio2008.Start();
        }

it starts Visual Studio 2012.exe and im looking for VS2008.exe to start. The reason for all this is that I need to open a report which only seems to work in VS2008

Posted 7-May-13 21:17pm

bdeklerk

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Comments

Jochen Arndt 8-May-13 3:41am

You must escape back slashes in strings with another backslash:
openVisualStudio2008.StartInfo.FileName = "C:\\Program Files(x86)\\Microsoft Visual Studio 9.0\\Common7\\IDE\\devenv.exe";

2 solutions

Solution 2

I managed to get it working with the code above. Browsed to the exe then copies the path and pasted into my code.

Posted 7-May-13 22:51pm

bdeklerk

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bdeklerk · Accepted Answer · 2013-05-07T22:50:00

private void btnReport_Click(object sender, EventArgs e)
        {
            Process openVisualStudio2008 = new Process();
            openVisualStudio2008.StartInfo.FileName = @"C:\Program Files (x86)\Microsoft Visual Studio 9.0\Common7\IDE\devenv.exe";
            openVisualStudio2008.Start();
        }

I managed to get it working with the code above. Browsed to the exe then copies the path and pasted into my code.

Problem number 2. How will I get it to open a specific file now in the VS 2008 automatically?