How to set startup object in console application in C# using code?

Question

1.00/5 (1 vote)

See more:

Hi team.

Hope you doing well,this question is in regards the startup object in C# console application.
during my project i came to a point where i have to set the startup object using code(in stead using property),but i am unable to get the solution.Please help me.

Your assistance will be highly appreciated!!!

Thanks and have a nice day ahead..

Dinesh Suthar

Posted 10-Oct-13 17:55pm

Dinesh92

Add a Solution

Comments

Ron Beyer 11-Oct-13 0:05am

What do you mean "startup object"? Do you mean the static class/method that is executed first when the program runs?

[no name] 11-Oct-13 0:11am

yes but not purposely a static class,a normal class

Ron Beyer 11-Oct-13 0:24am

The method that is executed first must be static and called Main, it can be in a "normal" class, but the method must be marked static and the class is not instantiated before the method is called. You set the startup object in the project properties, it will let you select any class that has a static "Main" method.

[no name] 11-Oct-13 0:26am

yes i can set it through my IDE but i am not supposed to use the property,i need it to be through code.

ArunRajendra 11-Oct-13 0:41am

Any specific reason for not setting through IDE?

[no name] 11-Oct-13 0:46am

I am doing research in it.

Ron Beyer 11-Oct-13 1:31am

Main is the first thing called in your code, how do you expect to use code to specify a different main method? Code has to run from somewhere...

[no name] 11-Oct-13 2:40am

I am implementing inheritance,so there can be multiple classes hence multiple Main methods..

2 solutions

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

Richard MacCutchan · Answer 1 · 2013-10-10T21:36:00

Just add code to your main class to select the appropriate startup object based on some set of options. Something like:

C#

static void Main(string[] args)
{
    string opt = args[0];
    switch (opt)
    {
        case "foo":
            Console.WriteLine("foo case");
            FooClass foo = new FooClass();
            foo.main();
            break;
        case "bar":
            Console.WriteLine("bar case");
            BarClass bar = new BarClass();
            bar.main();
            break;
        default:
            Console.WriteLine("No case");
            break;
    }
}

Dinesh92 · Answer 2 · 2013-11-10T20:33:00

Solution 3

:) thank you I have solved this by myself..

Posted 10-Nov-13 20:33pm