Receiving Error in sprintf

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The following command getting a syntax error in VS 2005....

int sprintf((char *)cptr,const char *format[cOutBuffer[usLoop]]);

Posted 19-Nov-13 17:32pm

Baakki

Updated 19-Nov-13 18:02pm

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Ron Beyer 20-Nov-13 0:25am

Are you defining a function called sprintf, or trying to call sprintf? If you are calling it, you need something more like:

int wroteChars = sprintf((char*)cptr, const char *format[coutBuffer[usLoop]]);

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Aescleal · Answer 1 · 2013-11-19T18:24:00

First point - great telling us it's a syntax error: Any other clues/context?

Second point - unless you're doing some fixed field formatting that's really difficult to achieve with iostreams don't touch sprintf with a barge pole, use std::stringstream instead.

Third point - I'd be really wary of casting const away (which I presume you're doing with the first parameter lacking any other context). If you've declared cptr const somewhere else in your program it was presumably for a reason - i.e. it was pointing to something immutable. Scrubbing that protection is a bit daft.

Fourth point - your second parameter looks like a declaration of an array of arrays of pointers to char, it's not a variable name. That's probably what's causing the compiler to fall over in a twitching heap.

chandanadhikari · Answer 2 · 2013-11-19T18:25:00

Solution 2

hi,
try like this
int myVariable = sprintf((char *)cptr,const char *format[cOutBuffer[usLoop]]);

hope this helps

Posted 19-Nov-13 18:25pm

chandanadhikari