Dynamic Binding Of Hierarchy Data Structure To Treeview Control

CREATE TABLE [dbo].[TBL_TREE_HIERARCHY]
( 
	[NODE_ID] [INT] IDENTITY(1,1) NOT NULL, 
	[NODE_DESCRIPTION] [NVARCHAR](50) NOT NULL, 
	[UNDER_PARENT] [INT] NOT NULL
) 

CREATE PROCEDURE [dbo].[SSP_GET_HIERARCHY] AS
BEGIN 

	WITH ITERATE_NODES_RECURSIVE AS 
		(
		SELECT NODE_DESCRIPTION, NODE_ID, UNDER_PARENT, 0 AS LEVEL_DEPTH 
		FROM dbo.TBL_TREE_HIERARCHY 
		WHERE (NODE_ID IN(SELECT NODE_ID FROM dbo.TBL_TREE_HIERARCHY  
		WHERE (UNDER_PARENT = 0))) 
		UNION ALL 
		SELECT Super.NODE_DESCRIPTION, Super.NODE_ID,Super.UNDER_PARENT, 
			   Sub.LEVEL_DEPTH + 1 AS LEVEL_DEPTH 
		FROM dbo.TBL_TREE_HIERARCHY AS Super INNER JOIN ITERATE_NODES_RECURSIVE AS SUB ON 
		SUB.NODE_ID = SUPER.UNDER_PARENT
		) 

	SELECT NODE_DESCRIPTION, NODE_ID, CONVERT(INT, UNDER_PARENT) AS UNDER_PARENT, LEVEL_DEPTH 
	FROM ITERATE_NODES_RECURSIVE 
	ORDER BY LEVEL_Depth 

END

exec [SSP_GET_HIERARCHY]

insert into [TBL_TREE_HIERARCHY] values('Mathematics',0)
insert into [TBL_TREE_HIERARCHY] values('Algebra',1)
insert into [TBL_TREE_HIERARCHY] values('Geometry',1)
insert into [TBL_TREE_HIERARCHY] values('Triangle',3)
insert into [TBL_TREE_HIERARCHY] values('By Relative Length',4)
insert into [TBL_TREE_HIERARCHY] values('By Internal Angle',4)
insert into [TBL_TREE_HIERARCHY] values('Equilateral Triangle',5)
insert into [TBL_TREE_HIERARCHY] values('Scalene Triangle',5)
insert into [TBL_TREE_HIERARCHY] values('Isosceles Triangle',5)
insert into [TBL_TREE_HIERARCHY] values('Oblique > 90 Degree:Obtuse Angled Traingle',6)
insert into [TBL_TREE_HIERARCHY] values('Oblique < 90 Degree:Acute Angled Traingle',6)
insert into [TBL_TREE_HIERARCHY] values('Right Angled Triangle',6)
insert into [TBL_TREE_HIERARCHY] values('Elementary Algebra',2)
insert into [TBL_TREE_HIERARCHY] values('Abstract Algebra',2)
insert into [TBL_TREE_HIERARCHY] values('Linear Algebra',2)
insert into [TBL_TREE_HIERARCHY] values('All Sides are Equal',7)