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Basic Curves And Surfaces Modeler

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18 Apr 2012CPOL3 min read 246.6K   16.4K   117  
A basic demo of modeling curves and surfaces in OpenGL.
#if HAVE_CONFIG_H
#  include <config.h>
#endif

#include "stdafx.h"

#include "Bsp.h"
#include "MMath.h"

void bspline(int n, int t, point *control, point *output, int num_output)

/*********************************************************************

Parameters:
  n          - the number of control points minus 1
  t          - the degree of the polynomial plus 1
  control    - control point array made up of point stucture
  output     - array in which the calculate spline points are to be put
  num_output - how many points on the spline are to be calculated

Pre-conditions:
  n+2>t  (no curve results if n+2<=t)
  control array contains the number of points specified by n
  output array is the proper size to hold num_output point structures


**********************************************************************/

{
  int *u;
  double increment,interval;
  point calcxyz;
  int output_index;

  u=new int[n+t+1];
  compute_intervals(u, n, t);

  increment=(double) (n-t+2)/(num_output-1);  // how much parameter goes up each time
  interval=0;


  for (output_index=0; output_index<num_output-1; output_index++)
  {
    compute_point(u, n, t, interval, control, &calcxyz);
    output[output_index].x = calcxyz.x;
    output[output_index].y = calcxyz.y;
    output[output_index].z = calcxyz.z;
    interval=interval+increment;  // increment our parameter
  }
  output[num_output-1].x=control[n].x;   // put in the last point
  output[num_output-1].y=control[n].y;
  output[num_output-1].z=control[n].z;

  delete u;
}

double blend(int k, int t, int *u, double v)  // calculate the blending value
{
  double value;

  if (t==1)			// base case for the recursion
  {
    if ((u[k]<=v) && (v<u[k+1]))
      value=1;
    else
      value=0;
  }
  else
  {
    if ((u[k+t-1]==u[k]) && (u[k+t]==u[k+1]))  // check for divide by zero
      value = 0;
    else
    if (u[k+t-1]==u[k]) // if a term's denominator is zero,use just the other
      value = (u[k+t] - v) / (u[k+t] - u[k+1]) * blend(k+1, t-1, u, v);
    else
    if (u[k+t]==u[k+1])

      value = (v - u[k]) / (u[k+t-1] - u[k]) * blend(k, t-1, u, v);
    else
      value = (v - u[k]) / (u[k+t-1] - u[k]) * blend(k, t-1, u, v) +
	      (u[k+t] - v) / (u[k+t] - u[k+1]) * blend(k+1, t-1, u, v);
  }
  return value;
}

void compute_intervals(int *u, int n, int t)   // figure out the knots
{
  int j;

  for (j=0; j<=n+t; j++)
  {
    if (j<t)
      u[j]=0;
    else
    if ((t<=j) && (j<=n))
      u[j]=j-t+1;
    else
    if (j>n)
      u[j]=n-t+2;  // if n-t=-2 then we're screwed, everything goes to 0
  }
}

void compute_point(int *u, int n, int t, double v, point *control,
			point *output)
{
  int k;
  double temp;

  // initialize the variables that will hold our outputted point
  output->x=0;
  output->y=0;
  output->z=0;

  for (k=0; k<=n; k++)
  {
    temp = blend(k,t,u,v);  // same blend is used for each dimension coordinate
    output->x = output->x + (control[k]).x * temp;
    output->y = output->y + (control[k]).y * temp;
    output->z = output->z + (control[k]).z * temp;
  }
}

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License

This article, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)


Written By
Product Manager Mahindra & Mahindra
India India
Sharjith is a Mechanical Engineer with strong passion for Automobiles, Aircrafts and Software development.

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