dynamically create table in database and insert data

Question

0.00/5 (No votes)

See more:

hi,

i have a form which contains numericupdown control and a button,in running i give a number and click a button. then it will open form2 ,there it will create textboxes the number i give in numericupdown control.

my question is based on the number i have to create a table and columns and after insert the data which i have given in the textbox.i have the following classes

1.form1

C#

private void button1_Click(object sender, EventArgs e)
        {
            Form2 f = new Form2();
            global.count = Convert.ToInt32(numericUpDown1.Value.ToString());
            f.Show();
        }

2.form2
private void Form2_Load(object sender, EventArgs e)
{
for (int i = 0; i <global.count;> {
TextBox tb = new TextBox();
tb.Name = "TextBOX" + i;
tb.Size = new Size(100, 25);
tb.Location = new Point(25, 25 + (i * 30));
Controls.Add(tb);

}

}
DAL dal = new DAL();//dal class
string create = "create table MYTABLE()";//how to create columns dynamically

Posted 6-Aug-13 0:44am

prasadhp

Add a Solution

2 solutions

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

Gautam Raithatha · Accepted Answer · 2013-08-06T00:59:00

Solution 1

Use below code to generate query dynamically and execute it on database using your method:

C#

string create = "CREATE TABLE MYTABLE (";
for (int i = 1; i <= count; i++)
{
    create += "column" + i.ToString() + " INT";

    if (i != count)
        create += ",";
}
create += ")";

Posted 6-Aug-13 0:59am

Gautam Raithatha

Comments

prasadhp 6-Aug-13 8:19am

thanks a lot, plz send me insert c

md also

Gautam Raithatha 6-Aug-13 8:43am

what is your database datatype for corresponding columns of these textboxes?

Gautam Raithatha · Accepted Answer · 2013-08-06T02:57:00

Solution 2

Build insert query as below:

C#

string insert = "INSERT INTO MYTABLE (";
string values = string.Empty;

for (int i = 1; i <= count; i++)
{
    insert += "column" + i.ToString();
    TextBox txtbox = (TextBox)this.Controls.Find("TextBOX" + i.ToString(), true)[0];    //set textbox id to search as per your form
    values += "'" + txtbox.Text.Trim() + "'";   //omit single quotes if datatype is integer i.e. values += txtbox.Text.Trim();

    if (i != count)
    {
        insert += ",";
        values += ",";
    }
}
insert += ") VALUES (" + values + ")";

//insert code here

Posted 6-Aug-13 2:57am

Gautam Raithatha

Updated 6-Aug-13 2:58am

v2

Comments

prasadhp 7-Aug-13 2:13am

Index was outside the bounds of the array.get in below line
(TextBox txtbox = (TextBox)this.Controls.Find("TextBOX" + i.ToString(), true)[0];)

Gautam Raithatha 7-Aug-13 2:51am

Your text box ids start from 0 i.e. TextBOX0, TextBOX1, etc.
And in above code it finds from 1 i.e. TextBOX1, TextBOX2 etc.
So the last textbox will not be found in the loop (also from first iteration it will take value from wrong text box). Replace that line with below:

TextBox txtbox = (TextBox)this.Controls.Find("TextBOX" + (i - 1).ToString(), true)[0];

(I hope as a developer you must have solved such an issue.)