Biggger Integers in C++or java !

Question

0.00/5 (No votes)

See more:

I want to make big numbers and use them for arithmetics.
Numbers really..reallly ..reallly big ..(HOW MUCH IS THE LIMIT?)
Multiply two huge numbers and make it even bigger?
I want a plan to do it?
I dont plan to use any extra packages(GMP,BigInteger,LargeInteger, etc.. i already googled them).
What could possibly be the way to do such a thing!!!

Posted 13-Jan-15 0:50am

Member 11371701

Add a Solution

2 solutions

Solution 1

You can check the limits:
http://www.cplusplus.com/reference/climits/[^]

http://docs.oracle.com/javase/7/docs/api/java/lang/Integer.html[^]

Both c++ and java depend on the underlying architecture you use. So on an x32 system the register size is 32bits and bigger numbers are often faked by combining 2 registers (eax and edx). Support for even bigger numbers needs to be implemented in special functions because there is no hardware support. This will make them slower. This goes for both java and c++.

Advantage with java is that the jit compiler will compile the program for the actual architecture it runs on. So a c++ program compiled for a 32 bit system will not use 64bit register sizes when running on x64. A java program will use the larger registers because the java runtime will optimize for it automatically.

Good luck!

Posted 13-Jan-15 1:03am

E.F. Nijboer

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

Aescleal · Accepted Answer · 2015-01-13T01:12:00

The limit is the largest lump of address space your code can access after all the code is loaded. For a 32 bit process you're talking on the order of 2^(2^40).

To actual implement a large number:

- work out how you want to represent the number (fixed point or floating point)
- decide how much precision you want (fixed or variable number of bits)

then code up a class and supporting free functions that implements the data representation and all the arithmetic operations you need. The first two decisions colour what the rest of the class looks like so it's a bit hard to comment on any more implementation issues until you made those decisions.