Tips & Tricks: How to Sort a Collection by its Property Name?






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Sorting a Collection by its Property Name
Several times, we need to sort a collection based on some property name, e.g., we have an Employee
collection of type Person
. Person
consists of EmpId
, Name
, Age
, etc. Now as a user, I need to sort the collection in ascending or descending order either by EmpId
, Name
or Age
. So, how can I do this?
In this post, I will describe a simple technique by which you will easily be able to sort the collection without writing the implementation for each logic. Read the complete article and if you have any suggestions at the end, please don’t forget to share. Feedback is always highly appreciated.
Before going to the actual implementation, let us create our base class, i.e., Employee
having some properties like EmpId
and Name
.
public class Employee
{
public string Name { get; set; }
public string EmpId { get; set; }
}
Now, it’s time to create a class which will implement the sorting algorithm. Let us create a class named “FieldSort
” and implement the IComparer interface
. Let us make it little bit generic. Hence create the class of generic type T
and implement it from the generic IComparer interface
type of T
.
IComparer
has a method called Compare()
. Just implement it in your class. Now inside the Compare()
method, get the PropertyInfo
by doing a reflection and get the value of the property of each comparable object as string
. Use string.Compare()
to compare between the values and return the comparison result as integer.
Here is the full implementation of the class:
using System;
using System.Collections.Generic;
using System.Reflection;
namespace SortLibrary
{
public class FieldSort<T> : IComparer<T>
{
private string propertyName = string.Empty;
private SortOrder sortOrder = SortOrder.ASC;
private StringComparison stringComparisonMethod =
StringComparison.CurrentCultureIgnoreCase;
/// <summary>
/// Initializes a new instance of the <see cref="FieldSort<T>"/> class.
/// </summary>
/// <param name="propertyName">Name of the property.</param>
/// <param name="sortOrder">The sort order.</param>
/// <param name="compareMethod">The compare method.</param>
public FieldSort(string propertyName,
SortOrder sortOrder = SortOrder.ASC,
StringComparison compareMethod =
StringComparison.CurrentCultureIgnoreCase)
{
this.propertyName = propertyName;
this.sortOrder = sortOrder;
this.stringComparisonMethod = compareMethod;
}
/// <summary>
/// Compares the specified x with specified y.
/// </summary>
/// <param name="x">The original object x.</param>
/// <param name="y">The object y which will be compared.</param>
/// <returns></returns>
public int Compare(T x, T y)
{
PropertyInfo propertyInfo = x.GetType().GetProperty(propertyName);
if (propertyInfo != null)
{
string xValue = propertyInfo.GetValue(x, null).ToString();
string yValue = propertyInfo.GetValue(y, null).ToString();
if (xValue != null && yValue != null)
{
return (sortOrder == SortOrder.ASC)
? string.Compare(xValue, yValue, stringComparisonMethod)
: string.Compare(yValue, xValue, stringComparisonMethod);
}
}
return 0;
}
}
}
Now let us discuss how to call this sort in our application. If you have the list collection of your Employee
information, you need to create the instance of the class FieldSort
of type Employee
with the proper arguments and pass as a parameter to the method Sort()
of the List
collection. That’s it. Your collection will sort automatically based on the “propertyName
” argument you passed in the FieldSort
class instance. You don’t need to call the Compare()
method. The IComparer interface
will take care of it for you.
Let’s see the calling method:
EmployeeList.Sort(new FieldSort<Employee>("Name",
SortOrder.DESC,
StringComparison.CurrentCultureIgnoreCase));
Once called, you will see the collection sorted according to your algorithm.
Here’s the original collection used for this example:
Once sort is done, you will see the sorted collection (descending order):
So, go ahead and use this class wherever you need. Don’t forget to provide your feedback. They are always welcome.