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Posted 4 Feb 2005


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Manipulate XML data with XPath and XmlDocument (C#)

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4 Feb 2005CPOL4 min read
An article about manipulating XML source data.

Sample Image

Image 2


Based on a section of easy-to-read XML source data, I'll show you how to select and locate XML nodes and navigate through them using XPathNavigator and XPathNodeIterator. I will provide a few straightforward samples about XPath expression with which you could follow without difficulty. In the last part, there is some sample code to update, insert and remove XML nodes.

Some Concepts

  • XML - Extensible Markup Language, describe data structures in text format and with your own vocabularies, which means it does not use predefined tags and the meaning of these tags are not well understood.
  • XSL - Extensible Stylesheet Language, is designed for expressing stylesheets for XML documents. XSL is to XML as CSS is to HTML.
  • XML Transformation - is a user-defined algorithm that transforms a given XML document to another format, such as XML, HTML, XHTML. The algorithm is described by XSL.
  • XSLT - is designed for use as part of XSL, transforming an XML document into another XML document, or another type of document that is recognized by a browser, like HTML or XHTML. XSLT uses XPath.
  • XPath - is a set of syntax rules for defining parts of an XML document.

To keep this article simple and clear, I'll break it down into two parts, and put XSL, XSLT to my next article.

Using the code

Here is the source XML data:

<?xml version="1.0" encoding="ISO-8859-1"?>
  <cd country="USA">
    <title>Empire Burlesque</title>
    <artist>Bob Dylan</artist>
  <cd country="UK">
    <title>Hide your heart</title>
    <artist>Bonnie Tyler</artist>
  <cd country="USA">
    <title>Greatest Hits</title>
    <artist>Dolly Parton</artist>

If you want to select all of the price elements, here is the code:

using System.Xml;
using System.Xml.XPath;
string fileName = "data.xml";
XPathDocument doc = new XPathDocument(fileName);
XPathNavigator nav = doc.CreateNavigator();

// Compile a standard XPath expression
XPathExpression expr; 
expr = nav.Compile("/catalog/cd/price");
XPathNodeIterator iterator = nav.Select(expr);

// Iterate on the node set
  while (iterator.MoveNext())
     XPathNavigator nav2 = iterator.Current.Clone();
     listBox1.Items.Add("price: " + nav2.Value);
catch(Exception ex) 

In the above code, we used "/catalog/cd/price" to select all the price elements. If you just want to select all the cd elements with price greater than 10.0, you can use "/catalog/cd[price>10.0]". Here are some more examples of XPath expressions:

/catalogselects the root element
/catalog/cdselects all the cd elements of the catalog element
/catalog/cd/priceselects all the price elements of all the cd elements of the catalog element
/catalog/cd[price>10.0]selects all the cd elements with price greater than 10.0
starts with a slash(/)represents an absolute path to an element
starts with two slashes(//)selects all elements that satisfy the criteria
//cdselects all cd elements in the document
/catalog/cd/title | /catalog/cd/artistselects all the title and artist elements of the cd elements of catalog
//title | //artistselects all the title and artist elements in the document
/catalog/cd/*selects all the child elements of all cd elements of the catalog element
/catalog/*/priceselects all the price elements that are grandchildren of catalog
/*/*/priceselects all price elements which have two ancestors
//*selects all elements in the document
/catalog/cd[1]selects the first cd child of catalog
/catalog/cd[last()]selects the last cd child of catalog
/catalog/cd[price]selects all the cd elements that have price
/catalog/cd[price=10.90]selects cd elements with the price of 10.90
/catalog/cd[price=10.90]/priceselects all price elements with the price of 10.90
//@countryselects all "country" attributes
//cd[@country]selects cd elements which have a "country" attribute
//cd[@*]selects cd elements which have any attribute
//cd[@country='UK']selects cd elements with "country" attribute equal to 'UK'

To update a cd node, first I search out which node you are updating by SelectSingleNode, and then create a new cd element. After setting the InnerXml of the new node, call ReplaceChild method of XmlElement to update the document. The code is as follows:

XmlTextReader reader = new XmlTextReader(FILE_NAME);
XmlDocument doc = new XmlDocument(); 

//Select the cd node with the matching title
XmlNode oldCd;
XmlElement root = doc.DocumentElement;
oldCd = root.SelectSingleNode("/catalog/cd[title='" + oldTitle + "']");

XmlElement newCd = doc.CreateElement("cd");

newCd.InnerXml = "<title>" + this.comboBox1.Text + "</title>" + 
        "<artist>" + artist.Text + "</artist>" +
        "<price>" + price.Text + "</price>";

root.ReplaceChild(newCd, oldCd);

//save the output to a file

Similarly, use InsertAfter and RemoveChild to insert and remove a node, check it out in the demo. When you run the application, make sure that "data.xml" is in the same directory as the EXE file.

Points of Interest

Anyway, XmlDocument is an in-memory or cached tree representation of an XML document. It is somewhat resource-intensive, if you have a large XML document and not enough memory to consume, use XmlReader and XmlWriter for better performance.


Version 1.0, it's my first article on CP, I expect there are many flaws. The XML source data and the knowledge comes from the web and MSDN, I just wrote a demo app to show them. No copyright reserved.



This article, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)


About the Author

Michael Chao
Canada Canada
No Biography provided

Comments and Discussions

General5 * Pin
Thava Rajan4-Nov-14 1:40
professionalThava Rajan4-Nov-14 1:40 
Questionhow to get the subchild attribute value of a tag if all childs have same tag name Pin
Member 111223268-Oct-14 3:35
MemberMember 111223268-Oct-14 3:35 
QuestionMy vote of 4 Pin
Alireza_136219-Aug-13 0:05
MemberAlireza_136219-Aug-13 0:05 
GeneralMy vote of 5 Pin
Member 806697717-Apr-13 10:26
MemberMember 806697717-Apr-13 10:26 
QuestionWord document XML Pin
Member 984829019-Feb-13 15:27
MemberMember 984829019-Feb-13 15:27 
Questionhaving some issue for if root as <catalog xmlns="xyzvalue"> Pin
Hemant Singh Rautela29-Jan-13 23:53
professionalHemant Singh Rautela29-Jan-13 23:53 
QuestionLike to access the XML of this format Pin
platso_58824-Jul-12 23:23
Memberplatso_58824-Jul-12 23:23 
GeneralMy vote of 4 Pin
Itz.Irshad8-Jul-12 21:35
MemberItz.Irshad8-Jul-12 21:35 
GeneralMy vote of 4 Pin
anver sadat16-May-12 2:41
Memberanver sadat16-May-12 2:41 
QuestionXml data with XPath and XmlDocument Pin
Fistum Mekuria25-Apr-12 5:49
MemberFistum Mekuria25-Apr-12 5:49 
GeneralMy vote of 4 Pin
Amit kumar pathak31-Mar-12 6:58
MemberAmit kumar pathak31-Mar-12 6:58 
Question[My vote of 1] Namespace attribute breaks your example Pin
msdevtech17-Feb-12 4:43
Membermsdevtech17-Feb-12 4:43 
Questionvote 5 Pin
tiktaktoe18-Jul-11 21:00
Membertiktaktoe18-Jul-11 21:00 
GeneralMy vote of 5 Pin
YSDen12322-Jun-11 23:39
MemberYSDen12322-Jun-11 23:39 
GeneralMy vote of 5 Pin
Radhika Vyas6-May-11 1:01
MemberRadhika Vyas6-May-11 1:01 
GeneralMy vote of 1 Pin
Milos Culic22-Dec-10 0:19
MemberMilos Culic22-Dec-10 0:19 
GeneralMy vote of 5 Pin
XtErMiNaToR10224-Nov-10 2:38
MemberXtErMiNaToR10224-Nov-10 2:38 
GeneralMy vote of 5 Pin
Dell.Simmons28-Oct-10 16:01
MemberDell.Simmons28-Oct-10 16:01 
GeneralGreat for beginners Pin
umerjafer30-Sep-10 8:47
Memberumerjafer30-Sep-10 8:47 
GeneralXML and SQL 2005/2008 Express with an XML field Pin
larry Williams31-Aug-10 14:15
Memberlarry Williams31-Aug-10 14:15 
GeneralAwesome! Pin
erat1233-Jun-10 5:58
Membererat1233-Jun-10 5:58 
GeneralGet value of an element on the basis of two attribute values Pin
NarVish30-Apr-10 3:04
MemberNarVish30-Apr-10 3:04 
GeneralPlease go thru another good example. Pin
shijoforum23-Oct-09 6:28
Membershijoforum23-Oct-09 6:28 
GeneralThank you Pin
xanmichaels29-Jun-09 12:43
Memberxanmichaels29-Jun-09 12:43 
GeneralCan't figure out how to read my xml Pin
sraelgaiznaer14-Jun-09 17:43
Membersraelgaiznaer14-Jun-09 17:43 

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