So the task is to create a Geometric series which halves

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This is my question:
Write C code (using a for loop) to create and print an array GS that stores the first 10 terms of the geometric sequence that halves each time:
{1/2, 1/4, 1/8, 1/16, ... 1/1024 }

My Semi-solution
is to use a for loop from 1:10
and use the formula 1/(2)^2
then print the array?

Posted 9-Dec-15 16:20pm

Member 12197225

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Comments

Sergey Alexandrovich Kryukov 9-Dec-15 22:33pm

What have you tried so far?
Just one hint: beware of integer division: if the value is supposed to be less than one, it returns zero, that is, integer part of result.
—SA

phil.o 9-Dec-15 23:02pm

You can proceed :) Trial and error is a necessary process if you want to become a developper.
Start from your pseudo-code -> code -> compile -> test -> debug -> code -> compile, etc.
While at this stage, if you do have a specific issue with the code you wrote, we will be glad to help.
Tip: the variable of your intended for-loop should appear in the formula.

[no name] 9-Dec-15 23:26pm

"the variable of your intended for-loop should appear in the formula" - You cannot categorically assert this.

phil.o 9-Dec-15 23:31pm

In the context described in the question, I think I can, yes, but I'll be glad you explain me why not :)

[no name] 9-Dec-15 23:39pm

There is more than one way of implementing the 1/(2)^2 in a loop and I would suggest avoiding any that employ the loop variable. Let's call that a hint.

phil.o 10-Dec-15 0:48am

Well, as I said, that was just a contextual hint from what OP has given. I don't really see why you don't get that. Of course there are several solutions to this exercise; unfortunately, there is no generic-universal answer covering them all.
Hint: contextual is an important concept here.

[no name] 10-Dec-15 3:18am

"Hint: contextual is an important concept here." How exactly? I think I have made a reasonable comment which you have not refuted. I cannot see how a good solution would involve the loop variable and that is the advice I wish to convey to the OP. If you can propose a good solution that does then share it with us.

[no name] 9-Dec-15 23:17pm

You are on the right track. Compared with some simple exercises presented here this one is quite illuminating.

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Member 12197225 · Answer 1 · 2015-12-09T17:31:00

Solution 1

so this is my solution now:

int Initial=0

Initial=input('Enter initial value: ')
scanf("%d", Initial);

for i =1:10 {
y(i)=(Initial)*(0.5);
}
end

Posted 9-Dec-15 17:31pm

Member 12197225

Comments

[no name] 10-Dec-15 3:28am

Have you read the comments? I would suggest you do as phil.o suggests, code it up, run it and see what happens. You will learn by this. You can do it all with only integers - no floating points.