Sorting a multi-dimensional list<string> c#

Question

1.50/5 (2 votes)

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I have this code to sort/order a List but it does not work

C#

public List<List<string>> OrderBy()
    {
        List<List<string>> listOrderBy = new List<List<string>>();
        for (int i = 0; i <= gvFilters.Rows.Count - 1; i++)
        {
            List<string> track = new List<string>();
            TextBox txtOrder = (TextBox)gvFilters.Rows[i].FindControl("txtOrder");
            DropDownList drpTableName = (DropDownList)gvFilters.Rows[i].FindControl("drpTableName");
            DropDownList drpFieldName = (DropDownList)gvFilters.Rows[i].FindControl("drpFieldName");
            track.Add(txtOrder.Text);
            track.Add(drpTableName.SelectedValue.ToString() + "." + drpFieldName.SelectedValue.ToString());
            listOrderBy.Add(track);
        }
        listOrderBy.OrderBy(l => Double.Parse(l[0]));
        return listOrderBy;
    }

My input are these:

1, Salutation
4, LastName
3, MiddleName
2, FirstName
5, Gender

The output should be

1, Salutation
2, FirstName
3, MiddleName
4, LastName
5, Gender

What I have tried:

I tried the code above and it did not work.

Posted 15-Feb-16 14:34pm

bjay tiamsic

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Comments

Sergey Alexandrovich Kryukov 15-Feb-16 22:30pm

There is no such thing as "multi-dimensional list".
—SA

1 solution

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bjay tiamsic · Accepted Answer · 2016-02-15T16:03:00

To share to others engaging to this kind of problem. Here's the solution I found:

Need to create a class for your requirement

C#

public class OrderFields
{
    public int OrderNo { get; set; }
    public string OrderField { get; set; }

    public OrderFields(int num, string field)
    {
        OrderNo = num;
        OrderField = field;
    }
}

Then use this class as your List<>

C#

public List<OrderFields> OrderBy()
    {
        List<OrderFields> listOrderBy = new List<OrderFields>();
        for (int i = 0; i <= gvFilters.Rows.Count - 1; i++)
        {
            TextBox txtOrder = (TextBox)gvFilters.Rows[i].FindControl("txtOrder");
            DropDownList drpTableName = (DropDownList)gvFilters.Rows[i].FindControl("drpTableName");
            DropDownList drpFieldName = (DropDownList)gvFilters.Rows[i].FindControl("drpFieldName");
            string ordervalue = drpTableName.SelectedValue.ToString() + "." + drpFieldName.SelectedValue.ToString();
            listOrderBy.Add(new OrderFields(Convert.ToInt32(txtOrder.Text), ordervalue));
        }
        listOrderBy.Sort(delegate(OrderFields x, OrderFields y)
        {
            return x.OrderNo.CompareTo(y.OrderNo);
        });
        return listOrderBy;
    }