Need SQL query to get following output. The "paid amount" & "received amount" columns are already present in my table. Want to generate "invested amount" using SQL.

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|Paid Amount | Received Amount | Invested Amount
| 10000      |    --           |  10000
|   --       |   8000          |   2000
|  5000      |    --           |   7000
|   --       |   4000          |   3000

What I have tried:

I am able to do it in MS Office Excel. But want to do it in my C# code.

Posted 26-Jun-17 19:03pm

100RABHA

Updated 26-Jun-17 20:42pm

v2

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Tom Wauters 27-Jun-17 1:47am

How are the columns of paid amount and received amount orderd? Do they have some kind of datetime column? And in the title you say you want to use SQL but in 'What I have tried' it's c#.

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Rajib.Rudra · Answer 1 · 2017-06-26T19:52:00

Solution 1

Select a.*, (Select SUM(Paid-Received) From #temp b where b.Code<=a.code) As Invested From #temp a Order By a.Code

Posted 26-Jun-17 19:52pm

Rajib.Rudra

RAMASWAMY EKAMBARAM · Answer 2 · 2017-06-26T20:00:00

You have not indicated the structure of the table but I can do this in Oracle (I don't use Sql Server):

create table investments
(
 slno number primary key,
 type char(1),
 amount number 
)
;

I insert some records:

insert into investments values (1, 'P', 10000);
insert into investments values (2, 'R', 8000);
insert into investments values (3, 'P', 5000);
insert into investments values (4, 'R', 4000);
insert into investments values (5, 'P', 2000);
insert into investments values (6, 'P', 6000);
insert into investments values (7, 'R', 3000);

The select query is:

select slno, 
case type when 'P' then to_char(amount) else '---' end paid,
case type when 'R' then to_char(amount) else '---' end received,	
sum(amount * case type when 'P' then 1 else -1 end) over (order by slno) invested
from investments	
order by 1

Tom Wauters · Answer 3 · 2017-06-26T20:42:00

Solution 3

You could use the lag function to get the previous row

SELECT value - lag(value) OVER (ORDER BY Id) FROM table

and then use the iif statement to see if you need to add or subtract

Posted 26-Jun-17 20:42pm

Tom Wauters