c# read from xml file

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Hello,

I have and xml file, like this:

XML

<MyXMLFile>
  <SerialNumber>111</SerialNumber>
  <Name>MyName</Name>
  <Size X="10" Y="12" />
  </MyXMLFile>

The user who creates the XML data file, can change the order of the elements.
For example, "size" element can be before "name" element.

I have to read the whole data of this file.

As far as I know, XMLReader can't go back from it's position.
So one solution I thought about, is to create an xml reader and destroy it, again and again.
For example:

C#

XmlReader xmlReader = XmlReader.Create(strXMLFileName);

xmlReader.ReadToFollowing(XMLNODE_Size);
int sizeX = Convert.ToInt32(xmlReader.GetAttribute("X"));
int sizeY= Convert.ToInt32(xmlReader.GetAttribute("Y"));
xmlReader.Close();

xmlReader = XmlReader.Create(strXMLFileName);
xmlReader.ReadToFollowing(XMLNODE_NAME);
xmlReader.ReadStartElement();
string name = xmlReader.ReadString();
xmlReader.ReadEndElement();
xmlReader.Close();

Is there a better way to do it, instead of close and reopen the xmlReader?
(I want also to read the attibutes where there are.)

Thanks

Posted 5-Nov-12 0:41am

user_code

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Comments

Storxstar 5-Nov-12 6:45am

Not sure if this will help but try using a while loop. While(XmlReader.Read())

3 solutions

Solution 3

//Method to read XML File and feel out
dropdownlist

C#

public void GetAllLocations()
       {
           DataSet ds = new DataSet();
           ds.ReadXml(Server.MapPath("~\\App_Data\\Location.xml"));

           try
           {
               if (ds.Tables[0].Rows.Count > 0)
               {
                   DDLLocation.Enabled = true;
                   DDLLocation.DataSource = ds;
                   DDLLocation.DataTextField = "LocationName";
                   DDLLocation.DataValueField = "LocationName";
                   DDLLocation.DataBind();
                   DDLLocation.Items.Insert(0, new ListItem("(Please Select)", Convert.ToString(0)));   // Add as first item

               }
               else
               {
                   DDLLocation.Items.Insert(0, new ListItem("Location not found", Convert.ToString(0)));
                   return;
               }

           }
           catch (Exception ex)
           {
               lblMessage.Text = "Load Location... " + ex.Message.ToString();
               return;
           }

       }

Posted 17-Mar-14 22:56pm

Fadao

Solution 2

//XML DATA

XML

<mydata>
  <admin>
    <username>
      admin
    </username>
    <password>
      admin1111
    </password>
  </admin>


  <admin>
    <username>
      admin1234
    </username>
    <password>
      1234
    </password>
  </admin>
</mydata>

//Method to read XML File

C#

XmlDocument xDoc = new XmlDocument();
          xDoc.Load("login.xml"); //XML File name (if winforms keep the XML file in bin directory)

         //Case 1: When only one value in xml File

          string username = xDoc.SelectSingleNode("mydata/admin/username").InnerText.Trim();
          string password = xDoc.SelectSingleNode("mydata/admin/password").InnerText.Trim();

         //Case 1 Ends

          //Case 2: when more than one value in xml File (looping)

          var mydata = xDoc.SelectNodes("mydata");
          for (int i = 0; i < mydata.Count; i++)
          {
              foreach (XmlNode node in mydata[i].ChildNodes)
              {
                  string uname = node.SelectSingleNode("username").InnerText.Trim();
                  string pwd = node.SelectSingleNode("password").InnerText.Trim();
              }
          }

//Case 2 Ends

Posted 6-Nov-13 1:20am

Bijuvs

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MT_ · Accepted Answer · 2012-11-05T00:53:00

Try using XmlDocument.

It goes something like this

C#

XmlDocument xDoc = new XmlDocument();
xDoc.Load("YourFile.Xml");

string sizeValue = xDoc.DocumentElement.SelectSingleNode("Size").InnerText;
string nameValue = xDoc.DocumentElement.SelectSingleNode("Name").InnerText;
string serialNumbersizeValue = xDoc.DocumentElement.SelectSingleNode("SerialNumber").InnerText;

Hope that helps. If it does mark the answer as solution/upvote.

Thanks
Milind