ArrayList contains problem

Question

1.60/5 (2 votes)

See more:

I read a txt with 2 way StreamReader and File.ReadAllText after add the list

C#

foreach (string line in File.ReadAllText(@openFileDialog1.FileName).Split(','))
               {
                   if (!ary.Contains(line.ToLower()) && line.Length > 2)
                   {
                       ary.Add(line.ToLower());
                   }
               }

but contains dont work add same strings
because the strings are similar but diffrent has code how can I fix it.
So how can I check contains with hashcode
I try list,dicitonary but dont change anything

C#

TextReader txt = File.OpenText(openFileDialog1.FileName);

is work but I dont split it with easily ,because my txt file a english book :)

Posted 27-May-13 9:41am

Member 9522119

Updated 27-May-13 9:53am

Maciej Los

v2

Add a Solution

Comments

Member 9522119 27-May-13 16:15pm

http://rapidshare.com/files/971436739/Yeni%20Metin%20Belgesi.txt it is my .txt file such as commands strings are diffrent hascode so both of them in list

Member 9522119 27-May-13 16:37pm

and sory textreader dont work such with others

2 solutions

Solution 2

Both the code in the question and "solution" are wrong, even if you think it "works". If something works but you don't understand how, it does not work.

First of all, never use the class ArrayList it was rendered obsolete as early as of .NET Framework v.2.0, when generics were introduced. It wasn't formally parked [Obsolete] just because there is nothing wrong in using it through some legacy code. For new development, you need to use the class System.Collections.Generics.List<>. It won't require potentially unsafe element type casting.

Now, what you really need to obtain correctly split lines is the class System.IO.File.ReadAllLines: http://msdn.microsoft.com/en-us/library/system.io.file.aspx[^].

Not only your code is redundant, it's also non-portable. Please see: http://en.wikipedia.org/wiki/End-of-line[^].

—SA

Posted 27-May-13 18:33pm

Sergey Alexandrovich Kryukov

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

Member 9522119 · Accepted Answer · 2013-05-27T11:02:00

Solution 1

Solved with "carriage return" split('\r') why? I dont know but its work ;)

Posted 27-May-13 11:02am

Member 9522119

v2

Comments

Sergey Alexandrovich Kryukov 4-Feb-14 14:39pm

This is called "cheating". How can you post such thing as the answer? And, worse, how could you "accept" it as the solution?
—SA