try playing with : X*X + Y*Y = const

which is the simple circle equation; naturally for any 0 < X < sqrt(const) you'll have 2 Y solutions, positive and negative, which is what you want

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Hello, Thank you for read my question. I'm appreciated with your concern.

I'm trying to**drawing a text based circle** without drawing header file or external class.

but include only "math.h" or any equivalent header/class like has "pi" value or "cosine/sine" function stuffs.

My goal is make a text based circle like next.

0000000000000000000000001

0000000000000000000001000

0000000000000000001000000

0000000000000010000000000

0000000000100000000000000

0000000010000000000000000

0000001000000000000000000

0000100000000000000000000

0100000000000000000000000

1000000000000000000000000

I need a circle curve equation code for C based programming language.

I tried to make a curve with using **"y=Cos(pi*x)"** but unfortunately it's not a plane circle curve.

Hence I'd like to know the circle curve equation example code in C based programming language.

Thank you!

I'm trying to

but include only "math.h" or any equivalent header/class like has "pi" value or "cosine/sine" function stuffs.

My goal is make a text based circle like next.

0000000000000000000000001

0000000000000000000001000

0000000000000000001000000

0000000000000010000000000

0000000000100000000000000

0000000010000000000000000

0000001000000000000000000

0000100000000000000000000

0100000000000000000000000

1000000000000000000000000

I need a circle curve equation code for C based programming language.

I tried to make a curve with using **"y=Cos(pi*x)"** but unfortunately it's not a plane circle curve.

Hence I'd like to know the circle curve equation example code in C based programming language.

Thank you!

try playing with : X*X + Y*Y = const

which is the simple circle equation; naturally for any 0 < X < sqrt(const) you'll have 2 Y solutions, positive and negative, which is what you want

which is the simple circle equation; naturally for any 0 < X < sqrt(const) you'll have 2 Y solutions, positive and negative, which is what you want

What you probably mean is a parameterized circle equation: Let variable t run from 0 to 2*PI in small increments and then calculate:

This will give you a set of coordinated for a circle around the origin with radius r.

If you want to print the circle in the way you showed in your question then consider that the space taken up by each print character is different in x and y direction. Hence you have to compensate this by applying a correction factor in the x or y calculation. Otherwise the circle will appear as an ellipse on your chart.

```
double x, y;
x = cos (t) * r;
y = sin (t) * r;
```

This will give you a set of coordinated for a circle around the origin with radius r.

If you want to print the circle in the way you showed in your question then consider that the space taken up by each print character is different in x and y direction. Hence you have to compensate this by applying a correction factor in the x or y calculation. Otherwise the circle will appear as an ellipse on your chart.

Comments

+5!

Thank you!

If i understand you well, you need to create 2 dimension array of chars (filled with

Have a look here: http://cboard.cprogramming.com/c-programming/101213-drawing-circle-ascii-character.html[^], here: http://en.wikipedia.org/wiki/Midpoint_circle_algorithm[^] and here: http://code-heaven.blogspot.com/2009/05/c-program-for-bresenham-circle-drawing.html[^]

Simple replace

`0`

- zero), then to replace some chars with other (`1`

- one) to imitate a circle... The size of array should be calculated based on `r`

(radius).Have a look here: http://cboard.cprogramming.com/c-programming/101213-drawing-circle-ascii-character.html[^], here: http://en.wikipedia.org/wiki/Midpoint_circle_algorithm[^] and here: http://code-heaven.blogspot.com/2009/05/c-program-for-bresenham-circle-drawing.html[^]

Simple replace

`SetPixel`

/`DrawPixel`

function with your own to replace char in a 2D-array of chars ;)
Comments

5.

Thank you, Carlo ;)

try:

```
class Program
{
const int N = 20;
static void Main()
{
char [, ] circle = new char[2*N+1, 2*N+1];
double phi, dphi = 0.5 / N;
phi = 0.0;
for (int y = 0; y < 2*N+1; y++)
for (int x = 0; x < 2*N+1; x++)
circle[y, x] = '0';
while (phi <= 2*Math.PI)
{
int x = (int) Math.Round( N + N * Math.Cos(phi));
int y = (int)Math.Round(N + N * Math.Sin(phi));
circle[y, x] = '1';
phi += dphi;
}
for (int y = 0; y < 2*N+1; y++)
{
for (int x = 0; x < 2*N+1; x++)
Console.Write(circle[y, x]);
Console.Write('\n');
}
}
```

Comments

Good job, Carlo!

+5!

This is what i was trying to explain in few word ;)

+5!

This is what i was trying to explain in few word ;)

Thank you, I followed your recipe. :-)

;)

+5

Thank you.

Thank you! It was so great helpful to me!

You are welcome.

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