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how can i multiply two double word using 8086 assembly language? :((
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If you mean X86 assembly language, rather than plain and unadulterated 8086 assemby, this[^] from stackoverflow might help.

I found this by using Google, you should try that as well.

Good luck. :)
 
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If my memory serves me right (haven't seen an 8086 (or assembly for that matter) for ages,
MOV EBX,OPR1
MOV EAX,OPR2
IMUL EBX

The result will be in EDX:EAX
 
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