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Convert XML into Object using XML serialization (Deserialize from XML)

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4.43/5 (6 votes)

Apr 17, 2012

CPOL

1 min read

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48032

XML Serialization

Introduction

In this tip, I’m explaining how we can convert XML into an object using XML Serialization.

Background

The same using LINQ is available in: http://www.codeproject.com/Tips/366993/Convert-XML-to-object-using-LINQ.

Using the code

For this example, I am using the following XML:

<ArrayOfStudent>
  <Student>
    <Name>Name1</Name>
    <Batch>I</Batch>
    <School>11/7/1997</School>
    <marks>
      <mark>
        <term>I</term>
        <science>46</science>
        <mathematics>50</mathematics >
        <language>46</language>
        <result>Pass</result>
        <comments>
          <teacher>good</teacher>
          <parent></parent>
        </comments>
      </mark>
    </marks>
  </Student>
</ArrayOfStudent>

Here the XML format is fairly simple – need to convert this xml to a class object containing object array (for <marks> node) using XML Serialization

A brief explanation about this XML structure

From top node–

    How do we convert this to an object?

    It is really simple ... We start from bottom i.e., <comments>.

  • Each student has name, batch and school
  • Each student has multiple term marks (e.g.: First Term/Second Term etc..)
  • In each term there will be separate comment about student performance (teacher/parent)

Step I: Convert <comments> to a class:

 <comments>
   <teacher>gooSDFSd</teacher>
   <parent></parent>
 </comments>

public class Comment
{
   [XmlElement("teacher")]
   public string TeacherComment { get; set; }
   [XmlElement("parent")]
   public string ParentComment { get; set; }
}

Tip: The XmlElement Attribute maps the property name with the XML node, i.e., the TeacherComment property maps with the XML node teacher.

Step II: Convert <mark> to class.

<marks>
      <mark>
        <term>I</term>
        <science>46</science>
        <mathematics>50</mathematics >
        <language>46</language>
        <result>Pass</result>
        <comments>
          <teacher>good</teacher>
          <parent></parent>
        </comments>
      </mark>
</marks>
[XmlType("mark")]
public class Mark
{
    [XmlElement("term")]
    public string Term { get; set; }
    [XmlElement("science")]
    public string Science { get; set; }
    [XmlElement("mathematics")]
    public string Mathematics { get; set; }
    [XmlElement("language")]
    public string Language { get; set; }
    [XmlElement("result")]
    public string Result { get; set; }
    [XmlElement("comments")]
    public Comment objComment = new Comment();
}

Here we bind Comment with in Mark class using as code below

[XmlElement("comments")]
public Comment objComment = new Comment();

As I mentioned in top a student can have multiple marks based on the term/session. So we need to create List<T> of marks as below:

[XmlArray("marks")]
public List<Mark> objMarkList = new List<Mark>(); 

Complete code looks like...

 public class Student
{
    [XmlElement("Name")]
    public string StudentName { get; set; }
    [XmlElement("Batch")]
    public string Batch { get; set; }
    [XmlElement("School")]
    public string School { get; set; }
    [XmlArray("marks")]
    public List<Mark> objMarkList = new List<Mark>();
}

Now we have created Student class with Mark which contain Comment

Let’s move to Deserialization.

XmlSerializer deserializer = new XmlSerializer(typeof(List<Student>));
TextReader textReader = new StreamReader(@"XML file path");
List<Student> stud;
stud = (List<Student>)deserializer.Deserialize(textReader);
textReader.Close();
foreach (var _stud in listStd)
{
   // Your code
}

What is happening here!!!

XmlSerializer deserializer = new XmlSerializer(typeof(List<Student>)); 

XmlSerializer deserializes from a stream , so we create a file stream from our XML file ,

TextReader textReader = new StreamReader(@"XML file path");

Then simply call Deserialize on the stream and cast the output to our desired type. Now the students list is populated with objects.