Change the last 2 characters of a string value in SQL

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How would I update the last two numbers in SQL.

Ex:
249691268200209200209

into:
249691268200209200231

What I have tried:

I just know how to select the data that ends with the tail end of those number I do not understand how to update the number.

SELECT data from data_table where data = '%0209';

I'm assuming:
UPDATE data_table set data = '%0231' WHERE data = '%0209';

Posted 3-Mar-20 8:32am

Member 14762163

Updated 26-Mar-20 22:45pm

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Richard Deeming · Answer 1 · 2020-03-03T09:09:00

A couple of options spring to mind:

SQL

UPDATE
    data_table
SET
    data = STUFF(data, Len(data) - 1, 2, '31')
WHERE
    data Like '%0209'
;

Or:

SQL

UPDATE
    data_table
SET
    data = Left(data, Len(data) - 2) + '31'
WHERE
    data Like '%0209'
;

NB: You need to use Like to match the pattern; otherwise, you'll only update records where the value is exactly equal to the string '%0209'.

STUFF (Transact-SQL) - SQL Server | Microsoft Docs[^]
LEFT (Transact-SQL) - SQL Server | Microsoft Docs[^]
LIKE (Transact-SQL) - SQL Server | Microsoft Docs[^]

ishan_shah · Answer 2 · 2020-03-26T22:47:00

Solution 2

We can solve it using the SUBSTRING Like the following update query :

UPDATE data_table
SET data = SUBSTRING(data, 1, LEN(data) - 2) + '31';

We can also permorm this query using replace method with Substring

UPDATE data_table
SET data = REPLACE(data, SUBSTRING(data, (LEN(data)-2),(LEN(data)+2)),'31')

Posted 26-Mar-20 22:47pm

ishan_shah

Comments

Richard Deeming 27-Mar-20 8:46am

Your first option is precisely what I posted in the comments three weeks ago.

Your second option is just wrong for a couple of reasons.
- The third argument to substring is the number of characters to return, not the index of the last character to return.
- If the last two digits appear anywhere else in the string, all instances will be replaced.

If you look at the example given in the question:
249691268200209200209 ⇒ 249691268200209200231
Your second example would incorrectly change the value to:
2496912682003120031